Bitwise OR operator evaluate each bit of the resultant value to 1 if any of the operand corresponding bit is 1. Bitwise AND Operator (&) is a binary operator, which operates on two operands and checks the bits, it returns 1, if both bits are SET (HIGH) else returns 0. I am using a function for the octree leaf count I implemented earlier to set the array to an appropriate size. We use bitwise OR operator to set any bit of a number. I expect the result to be like for 42 (0010 1010).Ĭan anyone provide a more elegant solution that is still readable? the result array will most likely be smaller that 8 values, but resizing is costly.This is not looking elegant and has two things that are disturbing: Result.SetValue( iteration, arrayPosition ) If ( (leafposition & 1) = 1 ) // LSB set? Flipping a bit is done by XOR-ing with a mask: set bits at the positions that you want to flip, and then. A byte is not just 8 values between 0 and 1, but 256 (28) different combinations (rather permutations). the bit at position 0 and the one at the third position. A bit is the most basic unit and can be either 1 or 0. Iteration++ //nodes are not zero-indexed. Count set bits using a lookup table Multiply 16-bit integers using an 8-bit multiplier Swap individual bits at a given position in an integer Check if a. Im trying to use masks and manipulating specific bits in a byte. So here's how I do that: int leafposition = _leafmask & _validmask My current implementation is using a while loop to find out if the LSB is set.
What I want to do now is returning an array of the leaf positions. I have a bitfield of type byte (so 8 bits only) that tells me where the leafs of the octree are (1 says leaf, 0 means no leaf, 8 nodes attached -> 8 bit). I was tyring to create a sparse octree implementation like the people at nVidia ("Efficient Sparse Voxel Octrees") were doing for their voxel things when I came across this issue:
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